150=-16t^2+18t+480

Solution for 150=-16t^2+18t+480 equation:

150=-16t^2+18t+480

We move all terms to the left:

150-(-16t^2+18t+480)=0

We get rid of parentheses

16t^2-18t-480+150=0

We add all the numbers together, and all the variables

16t^2-18t-330=0

a = 16; b = -18; c = -330;
Δ = b2-4ac
Δ = -182-4·16·(-330)
Δ = 21444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{21444}=\sqrt{4*5361}=\sqrt{4}*\sqrt{5361}=2\sqrt{5361}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{5361}}{2*16}=\frac{18-2\sqrt{5361}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{5361}}{2*16}=\frac{18+2\sqrt{5361}}{32}
$